Hello everyone,

I want to compile simple servlet which shows on the browser hello world.
I have jdk1.5 and tomcat 4.1 on windowx XP
I have given classpath = C:\tomcat1.4\comman\lib\servlet.jar
and java_home = C:\jdk1.5
Please help me!!!
whenever I compile it throws pacakge javax.servlet.http does not exist.

hi monali,
          i was facing similar problem earlier.i have given the class path in the environment variable itself.but i got the same error every times.i typed the classpath command in the command prompt every time.now its working.
like
set CLASSPATH=.;C:\Program Files\Apache Tomcat 4.0\common\lib\servlet.jar

i have inserted this line in my autoexec.bat file so i thought no need to set classpath everytime.
then i got the same error.
so whenever i want to execute a servlets or jsp program i will execute the command from the command prompt.

bye

Sonnu

Pls check whether servlet-api.jar or servlet.jar.

In case of Tomcat 5.0, servlet-api.jar is correct

servlet-api.jar

Ajit

Hello I was facing the same problem in my first servlet but now i can run my servlet I am having the jdk1.5 with apache tomcat 4 with window xp sp2 and i have set the environment variables as :
-------------------for JAVA_HOME---------
variable Name = JAVA_HOME
variable value = C:\Program Files\Java\jdk1.5.0_09
---------------for CATALINE_HOME------
variable name = CATALINA_HOME
variable name = C:\Program Files\Apache Group\Tomcat 4.1
-------------FOR CLASSPATH-----------
variable name = CLASSPATH
variable value = C:\Program Files\Apache Group\Tomcat 4.1\common\lib\servlet-api.jar;C:\Program Files\Apache Group\Tomcat 4.1\common\lib\jsp-api.jar;.;
-----------------------------------------
Note that I have pasted the jsp-api.jar and servlet-api.jar in my common lib directory from another version of apache tomcat.
also that the variables name and values are case sensitive
sorry my english is not good.
hope help you

Shahhussain