This must be really simple and yet I could not get it right. My need is to invoke a bat file from java servlet.

I could get the following info regarding the same but didn't work for me. The bat file is never invoked. It does not even enter catch block although it does not work properly. Any help?
try
{

String[] cmd = new String[3];


                cmd[0] = "cmd.exe" ;
                cmd[1] = "/C" ;
                cmd[2] = "C:\\Program Files\\apache-tomcat-6.0.18\\webapps\\mapping\\templatefileadjustment.b at";

Runtime.getRuntime().exec(cmd);
}
catch (IOException e) {

            response.getOutputStream().println(e);

            }

hi

i think its not able to locate the path,

can you try this way and check whether its running the batch file

java.io.File file = new java.io.File("C:\\Program Files\\apache-tomcat-6.0.18\\webapps\\mapping\\templatefileadjustment.b at");

      String path = file.getCanonicalPath();
            Runtime.getRuntime().exec(path);


---Raj

I have tried that. No luck yet!

I could understand the problem.

(1)With out using start, it is not working.
 (2)After using start, I have also realized that the bat file is invoked from a different place from the one it is actually placed. In my case, it is called from C:\\Program Files\\apache-tomcat-6.0.18\\bin. So if the bat file contains any commands which are relative to the path it is located, it will not work

(3)Some thing like this will work

Runtime.getRuntime().exec("cmd.exe /c start C:\\templatefileadjustment.bat");

Note that the spaces in path will give an error and so I had placed my bat file right under C: