I want to get the maximum of sum with one select statement.
The database is NorhtWind and this is the query.

select orderid, sum(quantity)
from [order details]
where orderid between 11000 and 11005
group by orderid
order by 2 desc

I know that i can use this statement:
select Top 1 orderid, sum(quantity)
from [order details]
where orderid between 11000 and 11005
group by orderid
order by 2 desc

or to use temporery tables but i am interested is there any different way to get only one row with maximum sum per orderid.
thanks
Alex

You can check it that select orderid, sum(quantity)
from [order details]
where sum (quantity) is maximum and orderid between 11000 and 11005

group by orderid
order by 2 desc



Love 4 all

qazi_nomi,

That won't work, would result in this error, as aggregate functions cannot be used in where.

An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause or a select list, and the column being aggregated is an outer reference.

Alex,
You can do it that way, as mentioned in your post. Otherwise, you can store them into TempTable and pick the max from there.

Hope that helps.
Cheers!

_________________________
-Vijay G
Strive for Perfection

i'm not clear about what you want to obtain: the first orderid with the maximun total quantity per orders (there could be more than one order with the same total quantity)? or are you trying to obtain the maximum total quantity per one order and a random orderid?

let's say you have the following data in the [Order Details] table:

OrderId Quantity
-----------------
1 5
1 1
2 20
3 5
3 15

what do you want to obtain for the above case?