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Old June 8th, 2003, 11:50 PM
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Default SQL Statement Error

I am building a web page that requires a member to login using a username and password. The username and password are stored as such:

uname = Request.Form("USERNAME")
pword = Request.Form("PASSWORD")

The username and/or password can be:

john
3456
pass52
password63

And so on.
I then use a SELECT SQL statement to search the database:

<%
Session("ConnGuestBook_ConnectionString") = "DBQ=" & Server.Mappath("db\Members.mdb") & ";DefaultDir=" & Server.Mappath("db\") & ";Driver={Microsoft Access Driver (*.mdb)};DriverId=25;FIL=MS Access;ImplicitCommitSync=Yes;MaxBufferSize=512;Ma xScanRows=8;PageTimeout=5;SafeTransactions=0;Threa ds=3;UID=admin;UserCommitSync=Yes;"
Session("ConnGuestBook_ConnectionTimeout") = 15
Session("ConnGuestBook_CommandTimeout") = 30

Dim CmdShowEntries
Dim MySQL
Set CmdShowEntries = Server.CreateObject("ADODB.Recordset")
MySQL = "SELECT BOOK1.* FROM BOOK1 WHERE ((USERNAME = '" & uname & "' ) AND (PASSWORD = '" & pword & "' ))"
CmdShowEntries.Open MySQL,Session("ConnGuestBook_ConnectionString"),3
%>


When I do this I get an error such as:

Microsoft VBScript runtime error '800a000d'
Type mismatch: '[object]'
confirm.asp, line 92

Does anybody know how I can fix this so it works with alpha-numeric inputs?
Thanks for your time!

Lord Farquhar
 
Old June 9th, 2003, 09:20 AM
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A few items...

1. Is this in ASP or ASP.NET

If it's .NET:
1. Take advantage of strong typing!
2. Use ADO.NET rather than classic ADO.

Which line is in #92?




Hal Levy
Daddyshome, LLC
 
Old June 9th, 2003, 06:41 PM
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It is just plain ASP. I do not have the .NET version yet. I really want it though!

Lord Farquhar
 
Old June 9th, 2003, 07:11 PM
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Which of the lines of the code you posted is line 92?

BTW you have some confusing variable names in your code. Eg MySQL is a popular and free database engine. Also prefixing a variable with cmd normally denotes an ADO Command object rather than a recordset object.

regards
David Cameron
 
Old June 9th, 2003, 07:15 PM
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Which line number is 92?


Hal Levy
Daddyshome, LLC
 
Old June 9th, 2003, 08:16 PM
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The line #92 is:

MySQL = "SELECT BOOK1.* FROM BOOK1 WHERE ((USERNAME = '" & uname & "' ) AND (PASSWORD = '" & pword & "' ))"

And the MySQL, is just a name that I have chosen.
I know it MySQL is it's own program, but that is just the string storage.


Lord Farquhar
 
Old June 9th, 2003, 08:27 PM
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I'd suggest your problem is that either uname or pword is an object of some sort and attempting to concetate them into a is causing an error. I can't see how else you would get a type mismatch error.

regards
David Cameron
 
Old June 9th, 2003, 10:21 PM
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The thing will work when it is like:

john
john_567
3465

But this won't:

pass5

That is the problem.

Lord Farquhar
 
Old June 9th, 2003, 11:01 PM
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Why is this thread in an SQL Server group, when it's also running in the MS Access group?

Cheers
Ken

www.adOpenStatic.com
 
Old June 10th, 2003, 11:35 AM
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I feel so stupid! A few lines down I realized that that it changed pword to a null value! I realized it when I hard coded pword in the page! It is fixed now! Thanks for all of your help!

Sincerely,

Lord Farquhar





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