Hey cant u write ur own funtion for this simple problem? Anyway i shall state the same for u.
1. U can use the floor function to get the integral part of the decimal number. i.e on ur VB
.NET IDE type math.floor(UrDecimalNumber)
Eg.. Math.Floor(5.6) would yeild 5 as the result.
2. Then subtract this integral part that u get from the decimal number. This would give u the decimal part that u require.
Eg. 5.6 - 5 = 0.6 (Required Result)
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