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Old February 2nd, 2004, 11:03 PM
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Default Rounding Numbers

Hi. I'm having a slight problem with VB's automatically rounding numbers. Take the following scenario:

Dim number1 As Integer = 90
Dim number2 As Integer = 46
Dim number3 As Integer = (number2/number1)

What I want is number3 returned as a whole number. However, in the above example VB rounds number3 up to 1. I want to keep it 0 since 46 did not go into 90 1 time. I hope I've been clear.

Thanks in advance to anyone who spends time reading this and/or helping.

Old February 2nd, 2004, 11:14 PM
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46/90 is 0.51 and will therefore be rounded up to 1.
45/90 will be rounded down to 0.

The Int() and Fix() will return the result you are after but they behave differently with negative numbers, so check them out if you need to use negative numbers.
number3 = Int(number2/number1)

They say, best men are moulded out of faults,
And, for the most, become much more the better
For being a little bad.
Old February 3rd, 2004, 06:06 AM
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VB has an Integer division operator (\ not /) which does what you want.
46\90 => 0


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