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Old March 16th, 2006, 07:48 PM
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Default Find and Replace 2 characters at once!! HELP

Hi All... my brain is going to pop. I am writing a small application that allows you to cut and paste text from anything into a text box and then have it re-formatted taking out certain CRs and replacing them with others.

If it were a simple find and replace that would be no problem, but, this is what I want to do:

I want to find all instances of chr(34) and chr(46) (. & ") at the same time and replace them with . " # at the same time - make sense? (the reason I want to add the # is because I am going to newline that afterwards)

How can I find two characters together and replace with 3?

If I replace them seperately they will replace all instances of '.' (for instance) throughout the whole string. I only want to replace when the two (.") are next to each other.

here is some code I have been playing with - but it doesn't work as such! I must be close - the pain in my head tells me so ;)

Any tips much appreciated... Sco


firstfind = Chr(46) + Chr(13)
RemoveCharacters(TextBox1.Text, firstfind) >>> calls

    Public Function RemoveCharacters(ByRef strText As String, _
    ByRef strUnwanted As Char) As String
        Dim currLoc As Integer
        Dim StringLength As Integer
        Dim tmpChar As String

        StringLength = Len(strText)
        For currLoc = 1 To StringLength

            tmpChar = Mid(strText, currLoc, 2)
            If InStr(strUnwanted, tmpChar) Then
                Mid(strText, currLoc, 3) = Chr(46) + Chr(34) + Chr(35)
            End If

        RemoveCharacters = strText

    End Function

Old March 17th, 2006, 11:18 AM
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Fear not... I've cracked it! :)

Old March 18th, 2006, 01:40 AM
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Please post your solution so that others can benefit. Thanks.

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