HELP, I am having trouble figuring out how to..

nvillare · October 2nd, 2003, 12:08 AM

I am learning VB.net and am working from a book. I am having trouble figuring out one of their review exercises.

I have to write a program that inputs one number consisting of five digits from the user. The program then separates the number into its individual digits and prints the digits separated from one another by three spaces each. For example, if the user typed 12345 it would show
1 2 3 4 5

This is to use the command window for input and output. It says to assume the user will enter only 5 digits, and to use both divison and modulus operators.

Can someone please give me a push into the right direction!! The book doesn't explain how to do that.

Your help is greatly appreciated!!

Thanks!

nvillare

jorevil · October 2nd, 2003, 06:29 AM

Hi,

try this

        Dim i As Integer
        Dim strInput As String = ""
        Dim charArray As Char()
        Dim strOutput As String = ""

        strInput = "12345"

        charArray = strInput.ToCharArray()

        For i = 0 To charArray.Length - 1
            'strOutput += charArray(i) & " "
            strOutput = strOutput & charArray(i) & " "
        Next
        MessageBox.Show(strOutput)

nvillare · October 2nd, 2003, 08:33 AM

Thanks for the help. The only thing is, I have to use division and mod, to figure it out. I have no idea on that.

Thanks!

nvillare

jlick · October 2nd, 2003, 08:36 AM

Here it is in VB6. You will have to convert to VB.NET.
I used the mod & the interger division operator.

    Dim lngNumber As Long
    Dim strOutput As String

    ' Initialize values
    lngNumber = 88888
    strOutput = ""

    ' Loop until done.
    ' We will be removing the least significant digit
    ' at the end of each iteration.
    Do While lngNumber > 0

        ' Use Mod 10 to get the last digit, convert that
        ' to a string, add it and the spaces to the FRONT
        ' of the string so far.
        strOutput = CStr(lngNumber Mod 10) & _
                    " " & _
                    strOutput

        ' Remove the last digit.
        ' Note the \ truncates the fraction.
        lngNumber = lngNumber \ 10
    Loop

    Debug.Print strOutput

John R Lick
[email protected]

nvillare · October 2nd, 2003, 09:01 AM

Thanks, but why use mod 10? I am trying to understand how it works.

Thanks!

nvillare

jlick · October 2nd, 2003, 09:26 AM

X Mod Y gives the remainder when you divide X by Y. 21 / 10 is 2 remainder 1, so 21 Mod 10 = 1. Any number mod 10 will give you the last digit.

You use modâs often in daily life. For example if it is 10:45 AM, and you want to know what time it will be in 30 minutes, you use Mod 60. (45 + 30) Mod 60 = 75 Mod 60 = 15, so it would be 11:15 AM.

Hours use Mod 12 (or mod 24 for a 24 hour clock). 11:00 + 2 hours is 1:00... (11 + 2) Mod 12 = 13 Mod 12 = 1.

John R Lick
[email protected]

dbmathis · March 13th, 2005, 08:09 PM

I have been learning Java from a self tech book and I ran into the same exercise.

This is how I solved it. Just look at the algorisims and ignore the Java code.

Code:

// Chapter 2 :: Self Exercise 2.30

// Write an application that inputs one number consisting of five digits 
// from the user, separates the numbers unto its individual digits and prints 
// the digits separated from one another by three spaces each.

// For example, if the user types in the number 42339, the program should print
// 4   2   3   3   9

import java.util.Scanner;

public class Ch2_Ex30
{
    // main method begins execution of Java application
    public static void main( String args[] )
    {
        // create Scanner to obtain input from command window
        Scanner input = new Scanner( System.in );

        int userInput; // User input... Number to be separated.

        System.out.print( "Enter a five digit integer: " ); // prompt user.
        userInput = input.nextInt(); // read five digit integer from user's keys.

        int first  =  (userInput / 10000); // first digit
        int second =  (userInput % 10000) / 1000; // second digit
        int third  =  (userInput % 1000) / 100; // thrid digit
        int fourth =  (userInput % 100) / 10; // fourth digit
        int fifth  =  (userInput % 10); // fifth digit

        System.out.printf( "%d   %d   %d   %d   %d", first, second, third,
         fourth, fifth ); // display integer separated into individual digits.
    }
}