Syntax error =(

deean · June 19th, 2008, 05:21 AM

Hello, I'm new in VB...
I have VB code but there is an error and I do not know how to fix it.
Here is the code:

str = request.Form("txtSearch");
length = request.Form("txtSearch.value.length");
str_fix = "";
first = 1;
final = "";
word = 0;

for i=0 to length do
     if i = length or str[i] = ' ' then
         if str[i] <> "" then
        path="form/document[(.,'<%= request.Form(" & str_fix & ")%>')]//*";
        if first = 0 then: final += ' ';
        first = 0;
        final += str_fix;
        str_fix = "";
        word ++;
         end if

         while str[i+1] = ' ' and i+1 < length do
             i++;
         wend

     else
    str_fix += str[i];
next

if word > 1 then: path="form/document[(.,'<%= request.Form(" & final & ")%>')]//*";

BrianWren · June 19th, 2008, 04:51 PM

This is a syntax error. The colon specifies the end of a statement. So essentially you have something for VB to do if the test is true, but the something is unspecified. Use either:

Code:

    If word > 1 Then path = ...

or

Code:

    If word > 1 Then
        path = ...
    End If

Same deal with "if first = 0 then: final += ' ';"

Plus, I don't follow your meaning here at all:

Code:

    While str[i + 1] = ' ' And i + 1 < length do

The interpreter would try to resolve "length do". but that doesn't mean anything. It makes "do" an argument of the Sub length(). But "length" is in a position where a value is needed for the comparison.

Old Pedant · June 19th, 2008, 05:00 PM

I think Brian is wrong.

The syntax error is that you have a semicolon on the end of your statement!

C# and C++ and Java and JavaScript and C all use semicolons.

VB doesn't allow them.

Old Pedant · June 19th, 2008, 05:02 PM

And of course you can't use [...] in VB either.

If you want to write in C#, then write in C#. VB syntax is completely different.