Hi chaps,

Can anyone help me? I have an XML file that describes a list of options in a menu, with each item I have a link to a web file e.g. <link>http://MyFile.htm</link>, I am using XSL to transform the file into a webpage and am trying to use the link of the item in a <a href="<xsl:value-of select="link"/>"> but the parser tells me I can't put <xsl:value-of select="Link"/> in an attribute, I've looked around on the web but am unable to find any examples of people doing the same!

Can someone tell me how it's done?

Cheers

Pete

Hi,

The parser won't let you pass the attribute as such because there is an xsl attribute tag that allows to do what you want to do. The syntax would be as such,

<a>
   <xsl:attribute value="href">
      <xsl:value-of select="link"/>
   </xsl:attribute>
</a>

The xsl:attribute tag takes the attribute parameter of the anchor tag as its value. Anything you place between beginning and end of the xsl:attribute tag will be considered as input to the value parameter. Finally, you have to close the anchor tag.

Hope this helps. Any questions just let me know.

Abdel

Thanks abdel, I tried this but it doesn't seem to work, I get a Attribute 'value' is invalid on 'xsl:attribute'. error, I've checked that I am returning something from the link element and I am - I'm returning //lsrv004 for example.

Any ideas?

Pete

The easiest thing is to use an "Attribute value template":
<a href="{link}">
OR use the full syntax:
<a>
   <xsl:attribute name="href">
      <xsl:value-of select="link"/>
   </xsl:attribute>
</a>
I suggest yopu download Msxml parser 4 which has an excellent help file packed with examples.


--

Joe

Cheers Joe, that worked a treat, I'll down load that file.

Thanks again, and thankyou Abdel

Pete

Hi

Sorry the code snippet I gave had an error ('value' should always be 'name')which joe has corrected with his entry. Glad you got working in the end.

Abdel