hi

have this xml:

<TR>
<TD height="20">ABC Categories</TD>
<TD>VASC_Customer_Orders_Production</TD>
</TR>

<TR>
<TD height="20">ABC Categories</TD>
<TD>VASC_Product_HistoryAndForecast</TD>
</TR>

<TR>
<TD height="20">ABC Categories replacing</TD>
<TD>PASC_Supersessions</TD>
</TR>

<TR>
<TD height="20">Absence</TD>
<TD>Rental Europe Universe</TD>
</TR>

<TR>
<TD height="20">Absence</TD>
<TD>REO_SELA</TD>
</TR>

<TR>
<TD height="20">Absence / day</TD>
<TD>Rental Europe Universe</TD>
</TR>

how to get an output sorted on the first TD?
Thus result should be:

ABC Categories:
-VASC_Customer_Orders_Production
-VASC_Product_HistoryAndForecast

ABC Categories replacing:
-PASC_Supersessions

Absence:
-Rental Europe Universe
-REO_SELA

Absence / day:
-Rental Europe Universe

Use something like

<xsl:for-each select="TR">
  <xsl:sort select="TD[1]"/>
  <xsl:value-of select="TD[1]"/>:
  <xsl:value-of select="TD[2]"/>
</xsl:for-each>

There's no guarantee that "ABC" will sort before "absence" - this depends on the collating sequence used by the processor. XSLT 1.0 gives you very little control over this, XSLT 2.0 gives you more but the details are processor-dependent.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

the muenchian method helped me better. found it after looking around for a while.

for those who don't know Muenchian sorting method:
http://www.jenitennison.com/xslt/gro...muenchian.html

grzz, kristof