import org.xml.sax is deprecated

sax · November 10th, 2003, 12:26 PM

Hi All, Please help ... I am a beginner of using SAX with Java. I think I don't have the org.xml.sax.* classes in my java class. So, I downloaded "saxjava-1.0" from www.megginson.com (I hope I downloaded the correct one). I unzipped the file and put it in my Java folder. However, it doesn't work when I run my Java code. I think I might missed out something ... like didn't import the file to Java classes? If so, how can I do that? My java code is trying to read an XML file and print out how many books in the xml file. After compiled, it has the following message:

"package com.jclark.xml.sax does not exists"

and 2 compiler warnings:
C:\XML\BookCounter.java:12:warning:org.xml.sax.Han dlerBase in org.xml.sax has been deprecated.

C:\XML\BookCounter.java:21:warning:org.xml.sax.Par ser in org.xml.sax has been deprecated.

My java code as follow:
------------------------------
import org.xml.sax.*;

public class BookCounter extends HandlerBase
{
    public static void main (String args[]) throws Exception
    {
           (new BookCounter()).countBooks();
    }

        public void countBooks() throws Exception
        {
            Parser p = new com.jclark.xml.sax.Driver();
            p.setDocumentHandler(this);
            p.parse("file:///C:/books.xml");
        }
}
------------------------------------

armmarti · November 17th, 2003, 08:35 AM

Hi,

it'll be better to separately define a Handler class.

Code:

import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;

public class SimpleHandler extends DefaultHandler
{
  public static int bookCount = 0;

  public void startElement(String namespace, String localName, String qName, Attributes attributes) throws SAXException
  {
    if(localName.equals("book"))  {
      ++bookCount;
    }
  }
}

Then you can test it like this:

Code:

import org.xml.sax.XMLReader;
import org.xml.sax.helpers.ParserAdapter;
import java.io.IOException;
import org.xml.sax.SAXException;

public class TestSAX {
  public static void main(String[] args)
  {
    XMLReader reader = null;
    if(System.getProperty("org.xml.sax.parser") == null) {
      System.setProperty("org.xml.sax.parser",  "org.apache.xerces.parsers.SAXParser");
    }
    try {
      reader = new ParserAdapter();
      reader.setContentHandler(new SimpleHandler());
      reader.parse("books.xml");
      System.out.println("C = " + SimpleHandler.bookCount);
    } catch (SAXException ex) {
      ex.printStackTrace();
    } catch(IOException ioe) {
      ioe.printStackTrace();
    }
  }
}

I've set Xerces as the default SAX parser, although you can set your preferred SAX parser through JVM parameter.

Regards,
Armen