Hello,


I'm new to xslt and xml. I have a xml-document that looks like this :

<?xml version="1.0" standalone="yes"?>
<sessions version="1.0">
  <session name="Development">
    <libraries>
      <library name="contxtlib">
        <fullname>123</fullname>
        <super>true</super>
        <loadorder>8</loadorder>
      </library>
      <library name="xmllib">
        <fullname>xmllib.p</fullname>
        <super>true</super>
        <loadorder>12</loadorder>
      </library>
      <library name="clientdebuglib">
        <fullname>clientdebuglib.p</fullname>
        <super>true</super>
        <loadorder>3</loadorder>
      </library>
    </libraries>
  </session>
</sessions>

Now i want to sort this xml-file. The loadorder should be 3 then 8 and then 12 and not in this order. So it has to be sorted. I tried writing a xslt file but he doesn't sort my data.
My xslt file looks like this:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:template match="session">
    <xsl:copy>
      <xsl:apply-templates>
         <xsl:sort data-type="number" select="session/libraries/library/loadorder"/>
         </xsl:apply-templates>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="*">
    <xsl:copy>
      <xsl:apply-templates/>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

Everything could be wrong for me, i found this on the internet and made some changes but now i don't know whether it's good. All i want to to is sort the library's on loadorder.

thx a lot in advance

All you need for this is a single template in your xsl file:
Basically, as the xslt processor goes through your xml document it will attempt to apply the sort to each node-set, but the only node that contains a "loadorder" child element is the library node, so the sort will effectively be ignored for all other nodes.

hth
Phil

Thx a lot!!
With my xml i still had a problem because he didn't copy the attributes but with yours he does everything perfectly THX!