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Old June 4th, 2003, 07:20 PM
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Default document node order vs sort node order.

So I am grouping nodes by predicate on an attribute and sorted the nodes based on another attribute. I put these nodes into lines in a table. I want to have the lines in the table have alternating background colors. When I use xsl:number that returns the document order # of the node but what I want is the number of the node in the grouped & sorted order - otherwise the colors don't alternate they are just lumped together in pre-sorted/pre-grouped order.

How do I go about that?

Here is the grouping example,

<th>Method Stats</th>
<xsl:apply-templates select="Metric[Values/@per='method']">
     <xsl:sort select="Values/@total" data-type="number" order="descending"/>
</xsl:apply-templates>


Thanks,

JJ
 
Old June 5th, 2003, 09:33 AM
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try the position() function instead, it reflects the sorted order. I assume you're trying to do something like this:
<xsl:element name="tr">
<xsl:if test="position() mod 2 = 0">
   <xsl:attribute name="class">even</xsl:attribute>
</xsl:if>
...
</xsl:element>

hth
Phil
 
Old June 5th, 2003, 11:06 AM
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Yeah that was exactly what I was doing. Thanks for the help.





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