Below is a snippet of XSL that I'm working on. I am getting a list of files from an SQL database, and I'd like to display them in a table 4 columns wide. Trouble is, I can't predict how many items I will get, so I'm trying to use the position() function to insert a new row tag after every 4 files.


<TABLE Class="Files">
<xsl:variable name="columns" select="4"/>
<xsl:if test="position() mod $columns = 0">
<xsl:for-each select="TABLE/COLUMN">
 <xsl:value-of select="position() mod $columns"/>
  <TR>
    CODE TO START NEW ROW AND DISPLAY FILE
  </TR>
</xsl:if>
<xsl:if test="position() mod $columns > 0">
    CODE TO DISPLAY FILE WITHOUT NEW ROW
</xsl:if>
</TABLE>

I have added a line to display the value of "position() mod $columns = 0" within the for-each, so I can see that I am getting correct values (1, 2, 3, 0, 1, 2, 3, 0). The problem is, even when the calculation =zero, the xsl:if (bold above) NEVER evaluates to true. Is this a bug with MSXML3?

Any help is appreciated.

Ken

But where you test position is not the same as where you display it, after the for-each loop.

--

Joe

Thanks Joe,

Guess I was a little blind to that.