hi

have this:
<xsl:key name="translateLabel" match="PAGE/CONTENT/DB/RECORDS[@label = 'translatelabels']/RECORD/translation" use="../id"/>

used as: key('translateLabel',id)

possible to write selection in <xsl:key> when there's no result found with the value of 'id', the value of 'id' itself is displayed ?

Now, I'm writing each key() wihtin a <xsl:choose>.
Want to replace this by placing the selection already in <xsl:key>

Kabe

I think you need to give a clearer explanation of your problem.

It is worth including snippets of your xml and xslt and the expected output.

Regards
Bryan

I defined this key:
<xsl:key name="translateLabel" match="PAGE/CONTENT/DB/RECORDS[@label = 'translatelabels']/RECORD/translation" use="../id"/>

and applying like this:
<xsl:choose>
<xsl:when test="key('translateLabel','overviewtechnical') != ''"><xsl:value-of select="key('translateLabel','overviewtechnical')"/></xsl:when>
<xsl:otherwise>{overviewtechnical}</xsl:otherwise>
</xsl:choose>

My question is if it is possible to move the selection to the xsl:key itself, so I have only to use <xsl:value-of select="key('translateLabel','overviewtechnical')"/> and getting the same result

Sure, just add the predicate [.!=''] to the end of your match pattern in xsl:key.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Isn't this just a part of the solution? In case more options are available

now, u're just moving [.!=''] to xsl:key, but, when there's no value, the result remains empty, while I want to have the value of input back when there's no result (<xsl:otherwise> in my example here above).

... but i'm afraid this isn't possible

thx