hi

 I can only do simple xsl and got stuck into this one , i really hope someone can help me out.. I cant think of a soultion.

 This is my XML

 <root>
 <PageType>
   <Type>
    <ID>1</ID>
    <Position>Something</Position>
   </Type>
   <Type>
    <ID>2</ID>
    <Position>Something else</Position>
   </Type>
   ....
 </PageType>
 <PageLet>
   <Page>
      <ID>0</ID>
      <Page_type>1</Page_type>
   </Page>
   .....
   .....
   .....
 </PageLet>
 </root>

 i wish to sort PageLet/Page accoring to its position by Page_type.

 Please dont use a template because i dont know that you 'or cant use it

 Hope can some one help me out

 Many thanks in advance
 auser

Firstly, you haven't given a very clear specification of your requirements. Showing the required output file is usually enough to give people a clue as to what you're wanting.

Secondly, if you don't supply the XSLT code you have written so far, then it's very difficult for people to see where you are having problems or learning difficulties.

Thirdly: "Please don't use a template". Sorry, but writing sorting and grouping in XSLT 1.0 is hard enough if you use the full language, but trying to do it without templates is like asking someone to show you how to play a Beethoven piano concerto with one hand.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Ohh dear sorry my mistake.

oky , let me explain quicky. for example i have 10 PageTypes and 20 Pages in Pagelet . for simplicity i like to show the ID of the page sorted by the Page_type

<root>
 <PageType>
   <Type>
    <ID>1</ID>
    <Position>2</Position>
   </Type>
   <Type>
    <ID>2</ID>
    <Position>1</Position>
   </Type>
 </PageType>
<PageLet>
   <Page>
      <ID>0</ID>
      <Page_type>1</Page_type>
   </Page>
   <Page>
      <ID>11</ID>
      <Page_type>2</Page_type>
   </Page>
   <Page>
      <ID>22</ID>
      <Page_type>1</Page_type>
   </Page>
 </PageLet>
</root>

<xsl:for-each="//PageLet/Page">
   <xsl:sort select="//PageType/Type[ID=Page_type]/Position" data-type="number"/>
  <xsl:value-of select="ID"/>,
</xsl:for>

displays results as:

0,22,11


************
sorry for not explaining more

any comments?

again Thanks
br
auser

<xsl:sort select="//PageType/Type[ID=Page_type]/Position" data-type="number"/>

The problem is that the context changes inside the predicate: both ID and Page_type are taken as children of the Type element. You want

<xsl:sort select="//PageType/Type[ID=current()/Page_type]/Position" data-type="number"/>

MK

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Great 'Thumbs UP

It works just fine : )

now i know i should read more : / lol

Many thanks for this solution , if there is something besides xsl i can be of anyhelp please say.

mhkay <--- your the man

br
auser