i have following XML

<?xml version="1.0" encoding="ISO-8859-1"?>
<tree>
<tree-node id="123" parent="" expand="true">
<item-data>
<label>2</label>
</item-data>
</tree-node>
<tree-node id="565" parent="123" expand="true">
<item-data>
<label>1</label>
</item-data>
</tree-node>
</tree>

In my XSLT i have a following entry

<xsl:template match="item-data/*">
  <span class="nodeName"><a href=""><xsl:value-of select="label"/></a>
  </span>
</xsl:template>

I would like to know how do i extract the attribute "id" value of tree-node and supply that in the "a href". it should be somethign like this.

  <span class="nodeName"><a href="123">2</a></span>
  <span class="nodeName"><a href="565">1</a></span>

Please provide pointers.

Thanks,
Sandeep

<a href="{../@id}">

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Thanks for the reply. I tried using this way as you suggested what i get is blank value instead of proper attribute value.

    <xsl:template match="item-data/*">

        <span class="nodeName">
           <a href="table.jsp?a={../@id}" target="mainFrame"> <xsl:value-of select="label"/></a>
        </span>
    </xsl:template>

Please suggest.

Sorry, I missed that your context node was not the item-data but the child of item-data, so you need to go up to the grandparent - ../../@id

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

And of course select="label" isn't going to select anything, because you're already on the <label> element.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Thanks a lot. I too tried the same meanwhile :). It works now.