Hi All

I have an XML file like below:

<RailInformation>
    <Node1>Going</Node1>
    <OtherInfo/>
</RailInformation>
<RailInformation>
    <Node2>Going</Node2>
    <OtherInfo/>
</RailInformation>
<RailInformation>
    <Node3>Going</Node3>
    <OtherInfo/>
</RailInformation>


<RailInformation>
    <Node1>Coming</Node1>
    <OtherInfo/>
</RailInformation>
<RailInformation>
    <Node2>Coming</Node2>
    <OtherInfo/>
</RailInformation>
<RailInformation>
    <Node3>Coming</Node3>
    <OtherInfo/>
</RailInformation>

As you can see I have the rail information for coming and going. However, the information is not grouped together. I want that all the "Coming" information should be grouped in one group and all the "Going" information should be grouped in another group like the one presented below:

<AllInfoGoing>
    <Node1>Going</Node1>
    <OtherInfo/>
    <Node2>Going</Node2>
    <OtherInfo/>
    <Node3>Going</Node3>
    <OtherInfo/>
</AllInfoGoing>

<AllInfoComing>
    <Node1>Coming</Node1>
    <OtherInfo/>
    <Node2>Coming</Node2>
    <OtherInfo/>
    <Node3>Coming</Node3>
    <OtherInfo/>
</AllInfoComing>

I need to do this using XSTL. I would greatly appreciate any help provided.

Thanks & Regards,
- Anuj Mathur

Hi Anuj,
 First thing is, the xml element eg. <node1>, <node2>.... cant be grouped as there is different names. if i have common name like <node>Going</node> <node>Coming</node> would be a easy task for grouping.
U can use this url for further information(http://www.dpawson.co.uk/xsl/sect2/N4852.html). if u can give me exact xml i will help u out. My mail id [email protected].


Thanks &amp; Regards
Naveen.

>First thing is, the xml element eg. <node1>, <node2>.... cant be grouped as there is different names.

This isn't true. Muenchian grouping (http://www.jenitennison.com/xslt/grouping) allows grouping on any computed value, e.g. translate(name(), '0123456789', ,,).

However, I don't think this is a true grouping problem because the list of possible values is known statically. In fact, it's a very straightforward problem, and the only reason I didn't attempt to respond is that I can't see where the difficulty lies. It's something like this:

<AllInfoGoing>
  <xsl:for-each select="RailInformation[*[1]='Going']">
    <xsl:copy-of select="*"/>
  </xsl:for-each>
</AllInfoGoing>

<AllInfoComing>
  <xsl:for-each select="RailInformation[*[1]='Coming']">
    <xsl:copy-of select="*"/>
  </xsl:for-each>
</AllInfoComing>

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference