xslt copy-of

ppeou · August 22nd, 2003, 12:36 PM

hello,

i have an xml node with some html tags within it:
<myNode>This is bold and this is italics in HTML.</myNode>

i want to copy everything in the node, EXCEPT the node name.
if i use <xsl:copy-of select="myNode" />

my result is: <myNode>This is bold and this is italics in HTML.</myNode>

is there a way to only get:
This is bold and this is italics in HTML.

so that <myNode> </myNode> is not in the return string?

as for a note, if i use <xsl:value-of select="myNode" /> , the HTML tags are lost.

planoie · August 22nd, 2003, 12:45 PM

I think you should get what you want with this:

Code:

<xsl:value-of select="myNode" disable-output-escaping="no" />

------------------------
Peter
Somewhere outside
Boston, MA USA Earth

ppeou · August 22nd, 2003, 12:55 PM

hi planoie,

thanks for the suggestion and i gave it a try, but it did not give me the correct results, the result was the node value, without the html tags:

This is bold and this is italics in HTML.

what im looking for is:

This is bold and this is italics in HTML.

planoie · August 22nd, 2003, 02:09 PM

Ok, I just realized I made a mistake. Try disable-output-escaping="yes".
Maybe that will work. Otherwise, I think the transform is stripping or escaping the tags.

ppeou · August 22nd, 2003, 02:24 PM

gave that one a try also, but still the same result, i'll see what else i can find on the net,

thx again for your help

joefawcett · August 24th, 2003, 07:09 AM

Instead of

Code:

<xsl:copy-of select="myNode" />

try

Code:

<xsl:copy-of select="myNode/node()" />

--

Joe