Hi all,

Is there any way to write a XSLT that go through the whole xml (element, attribute) then create another xml? (Cannot specific any xml tag name on the xslt)

Thanks!!
Den

XML sample:

<customers>
  <customer>
    <firstname>hello</firstname>
    <lastname>world</lastname>
    <profile_info>
      <profile id="1" number="0" endDate="2005-07-07" />
      <profile id="2" number="0" endDate="2005-07-08" />
      <profile id="3" number="0" endDate="2005-07-09" />
    </profile_info>
  </customer>
</customers>

Please provide what output.xml u will be looking for. and sample xslt u have tried.

Thanks and Regards
Naveen.

Hi meetnaveen4u,

The output for now i want to be excatly the same as the sample i given. But in the future, i will add more optional element or attribute in XSLT so when the xml transform to another xml the optional field will exist.

Thanks!

You need the identity transform. There's an example of it here:
http://p2p.wrox.com/topic.asp?TOPIC_ID=21082
and it show an element being modified (monkey to new:monkey. You can also remove or add elements.



--

Joe (Microsoft MVP - XML)

Hi joefawcett,

Thank you for your information. That's what i need!!! One more question, after copy the whole original. I added the "optionalField" under the node "unsignedData", i have "Field_1" and "Field_2" under "optionalField". How can i assign the data under those fields? I cannot use <xsl:value-of select"Field_1">, because the variable is not exist in original xml.

THANKS!!!!

My Code:

<-- transform all node from original xml to new xml -->
<xsl:template match="node()|@*"/>
  <xsl:copy>
    <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
</xsl:template>

<-- add "optionalField" under "unsignedData" node -->
<xsl:template match="unsignedData">
  <xsl:copy>
    <xsl:apply-templates select="node()|@*"/>
    <xsl:element name="optionalField">
      <xsl:element name="Field_1"/>
      <xsl:element name="Field_2"/>
    </xsl:element>
  </xsl:copy>
</xsl:template>

I got it!!! Thanks for all !!

Hi All,

I got another question. How can i remove one of the element after transform? Let said the element is called "profile_info"?

Thanks!!

XML Code:

<customers>
  <customer>
    <firstname>hello</firstname>
    <lastname>world</lastname>
    <profile_info>
      <profile id="1" number="0" endDate="2005-07-07" />
      <profile id="2" number="0" endDate="2005-07-08" />
      <profile id="3" number="0" endDate="2005-07-09" />
    </profile_info>
  </customer>
</customers>


XSLT Code:

<-- transform all node from original xml to new xml -->
<xsl:template match="node()|@*"/>
  <xsl:copy>
    <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
</xsl:template>

Add an empty template that matches "profile_info": Obviously all children will be removed as well.

--

Joe (Microsoft MVP - XML)

Thanks Joe!

You Guyz are PRO!!!!