Hi All,

I have to import xyz.xsl in my main.xsl.

xyz.xsl contains:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<test>
<xsl:variable name="nxe_1" select="//para/note"/>
<test>
</xsl:stylesheet>

And main.xsl contains:
<?xml version="1.0" encoding="UTF-8"?>
<sample>
  <para>Sample para.<note>This Note is not to be translated</note>Sample para.</para>
</sample>

How will i use import and include for transformation to get

Output.xml:
<sample>
  <para>Sample para.<test><note>This Note is not to be translated</note></test>Sample para.</para>
</sample>

Corrections:

It's main.xml not main.xsl

Neither of your two .xsl files is a valid stylesheet.

I don't think xsl:include or xsl:import is likely to be part of the solution to your problem. It would be better to describe what you are trying to do.

I'd suggest the following:

<xsl:template match="*">
  <xsl:copy>
  <xsl:copy-of select="@*"/>
  <xsl:apply-templates/>
  </xsl:copy>
</xsl:template>

<xsl:template match="para/note">
  <test>
    <xsl:copy-of select="."/>
  </test>
</xsl:template>

This follows a standard design pattern for transformations of the form "copy everything except XYZ": you write one template rule for "everything" that does a (recursive) copy, and another for XYZ that does something different.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference