Hi all,

Given the following XML document...

<data>
 <letter id="sample">
  <group id="12345">
    <source id="12345">
    </source>
    <target id="12345">
    </target>
    <condition id="12345" />
  </group>
 </letter>
</data>

I'm trying to write an XSL transform which copies the document and replaces the numeric id attributes with random numbers.

I've nearly got this sorted although it works for when elements don't have an id attribute but not for when they do. I want to replace existing id attribute values as well. My transform is below;

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet extension-element-prefixes="java" xmlns:java="http://xml.apache.org/xslt/java"
    version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:variable name="random" select="java:java.util.Random.new()"/>
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="group|source|target|condition">
        <xsl:copy>
            <xsl:attribute name="id">
                <xsl:value-of select="java:java.lang.Math.abs(java:nextInt($rand om))"/>
            </xsl:attribute>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

I'm using Xalan and Oxygen to do the transforming.

Thanks in advance,

Chris

Simplest fix is just to reverse these two instructions:

            <xsl:attribute name="id">
                <xsl:value-of select="java:java.lang.Math.abs(java:nextInt($rand om))"/>
            </xsl:attribute>
            <xsl:apply-templates select="@*|node()"/>


If you write two attributes with the same name to the same element, the second one wins.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference