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Old February 14th, 2006, 05:10 AM
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Default How to combine two value-of selects?

Hi,
Anyone know how to do this? I have the following XML file...

<recipients>
    <item no="1">
        <phone>0046123456</phone>
    </item>
    <item no="2">
        <phone>0046987654</phone>
    </item>
</recipients>
<sendlog>
    <step no="1">
        <sent as_item="1">
            <status>STATUS 3</status>
        </sent>
        <sent as_item="2">
            <status>STATUS 1</status>
        </sent>
    </step>
</sendlog>

...and what I want to do is check if a phone number is listed, and if so, get the sendlog status of that number (a phone numbers @no is the same as the sendlogs @as_item).

I can get a phone numbers @no attribute like so:
<xsl:value-of select="//item[phone='0046123456']/./@no" />

And I can get the status of a @as_item number like so:
<xsl:value-of select="//sent[@as_item='2']/status" />

But I need to combine them. How do I use the result in the first value-of select in the second value-of select statement?

Any help on this is highly appreciated :)

 
Old February 14th, 2006, 05:44 AM
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Default

Use a variable

<xsl:variable name="x" select="//item[phone='0046123456']/./@no" />
<xsl:value-of select="//sent[@as_item=$x]/status" />


Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
 
Old February 14th, 2006, 06:20 AM
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Thank you very much for your help.

Ps. I have your book "XSLT 2:nd Edition" on my shelf here. Perhaps I need to look into it a bit again ;)





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