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Old February 17th, 2006, 04:14 PM
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Default Multiple String Replace

Hi,

I am new to XSLT and I want to do the following:

From a document that looks like this:

<content>
  <text>This is the var1 I want to var2</text>
  <replacements>
    <word>
      <from>var1</from>
      <to>text</to>
    </word>
    <word>
      <from>var2</from>
      <to>replace</to>
    </word>
  </replacements
</content>

I want to replace the 'from' element with the 'to' element on the 'text' element.

Any help will be appreciated.

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Old February 17th, 2006, 04:38 PM
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String replacement is easier in XSLT 2.0 than in 1.0.

Start with http://www.dpawson.co.uk/xsl/sect2/replace.html

Note also that there's a useful string-replace template at www.exslt.org.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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Old February 20th, 2006, 03:41 PM
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Thanx

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Old May 19th, 2008, 10:46 PM
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Hi mhkay, all,

I tried your xslt in the xlst 2.0 wrox book. How do I extend to multiple characters? For example "copyright" symbol as well.

My source:
<root>
<content>Register symbol® Copyright symbol© registration symbol again® trademark symbol™ copyright symbol again©</content>
</root>

My output:
<root>
<content>Register symbol#174; Copyright symbol© registration symbol again#174; trademark symbol™ copyright symbol again©</content>
</root>

Your XSL (slighly modified)

<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <!--
-->
    <xsl:param name="reg.search" select="'®'"/>
    <xsl:param name="reg.replace">
        <xsl:text><![CDATA[#174;]]></xsl:text>
    </xsl:param>
    <xsl:param name="copy.search" select="'©'"/>
    <xsl:param name="copy.replace">
        <xsl:text><![CDATA[#153;]]></xsl:text>
    </xsl:param>
    <!--
-->
    <xsl:template name="search-replace">
        <xsl:param name="text"/>
          <xsl:param name="search" select="document('replace.xml')/*/replace/from" />
        <xsl:choose>
            <xsl:when test="contains($text, $reg.search)">
                <xsl:value-of select="substring-before($text, $reg.search)"/>
                <xsl:value-of select="$reg.replace" disable-output-escaping="yes"/>
                <xsl:call-template name="search-replace">
                    <xsl:with-param name="text" select="substring-after($text, $reg.search)"/>
                </xsl:call-template>
            </xsl:when>
            <xsl:otherwise>
                <xsl:value-of select="$text"/>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>
    <!--
-->
    <xsl:template match="*">
        <xsl:copy>
            <xsl:copy-of select="@*"/>
            <xsl:apply-templates/>
        </xsl:copy>
    </xsl:template>
    <!--
-->
    <xsl:template match="text()">
        <xsl:call-template name="search-replace">
            <xsl:with-param name="text" select="."/>
        </xsl:call-template>
    </xsl:template>
    <!--
-->
</xsl:transform>


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Old May 19th, 2008, 10:48 PM
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One tag not needed. Forgot to omit

<xsl:param name="search" select="document('replace.xml')/*/replace/from" />

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Old May 20th, 2008, 02:47 AM
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Are you using XSLT 1.0 or 2.0? In 2.0, it's much easier to use the replace() function.

With the 1.0 solution, you basically need to call the search-replace template once for each from/to replacement pair. If you know statically how many replacements are needed (in your case two) then just call the template twice. If the number of replacements is a dynamic list, then you need another level of iteration, typically implemented using head-tail recursion.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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