total noob xslt question

mrscott · February 22nd, 2006, 02:21 PM

I'm sure this is a no brainer but my head hurts trying to figure this out... so please help.

I have xml like the following

<?xml version="1.0">
<doc xmlns:abc="ab:cd:ef:gh">
<title abc:font="Times New Roman">My Father Was A Monkey</title>
</doc>

I want to write some xslt to grab both the font attribute and the title value.

How the heck do I do this? I'm not used to writing xslt for xml that has namespaces declared (flame on), so I don't get how to reference the attribute here... Please help!

joefawcett · February 22nd, 2006, 02:28 PM

Add this to your xsl:stylesheet element:

Code:

xmlns:abc="ab:cd:ef:gh"

Then use something like:

Code:

<xsl:value-of select="/doc/title/abc:font"/>

in the sheet. The elements aren't in the "ab:cd:ef:gh" namespace so you can select these using XPath without prefixes.

I suggest this FAQ as a guide on namespace questions:

http://www.dpawson.co.uk/xsl/sect2/N5536.html

--

Joe (Microsoft MVP - XML)

mhkay · February 22nd, 2006, 03:35 PM

<xsl:template match="doc" xmlns:abc="ab:cd:ef:gh">
font: <xsl:value-of select="title/@abc:font"/>
title: <xsl:value-of select="title"/>
</xsl:template>

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

mrscott · February 22nd, 2006, 04:35 PM

Thank you both.