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Old March 1st, 2006, 08:54 PM
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Default Finding values from duplicated nodes

In the following XML example:


I am looking for the DTM02 value where the proceeding DTM01 value is 150 and then the DTM02 value where the preceeding DTM01 value is 151. However, when looping though all the parent nodes proceeding these nodes:

<xsl:for-each select="ClientData">

I can only retrieve the DTM02 value from the first set of DTM nodes where the DTM01 value is 232 (see the top of my example). I get that value twice, using either choose or if:
   <xsl:when test="DTM/DTM01 = '150'">
     <xsl:value-of select="substring(DTM/DTM02,5,2)"/>/<xsl:value-of select="substring(DTM/DTM02,7,2)"/>/<xsl:value-of select="substring(DTM/DTM02,1,4)"/>

or an if:

<xsl:if test="DTM/DTM01 = '151'">
  <xsl:value-of select="substring(DTM/DTM02,5,2)"/>/<xsl:value-of select="substring(DTM/DTM02,7,2)"/>/<xsl:value-of select="substring(DTM/DTM02,1,4)"/>

What is the best way to do this?
Old March 2nd, 2006, 05:21 AM
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First understand why your code doesn't work:

<xsl:when test="DTM/DTM01 = '150'">

returns true if the context node has a child DTM element that has a child DTM01 element whose string value is "150"

<xsl:value-of select="substring(DTM/DTM02,5,2)"/>

selects all the DTM02 children of all the DTM children of the context node, then takes the string value of the first node in this node-set (in document order). (In XPath 2.0 this will give you an error if there's more than one node in the node-set, to catch people making this common mistake).

You're making an assumption that the "DTM" in the second expression somehow means the particular "DTM" that you matched in the first expression, and of course it doesn't.

The way to do this kind of thing is with a single expression:


this selects all the DTM elements children of the context node with a child DTM01 element equal to "150", and then selects the DTM02 children of these selected DTM elements.

Michael Kay
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

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