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Old March 24th, 2006, 01:14 PM
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Default passing parameter to xsl file

I am a newbie to XML/XSL.

I am passing the parameter in the link as you can see in the below html example. All I want is based on the keyname value passed in the link I want to retreive the data from XML file and then display it in the webpage. The below code doesn't seem to work. It is not displaying anything at all.

If I hard code the value for example if I change the following line in XSL file from

<xsl:if test="@id=$keyname"> to
<xsl:if test="@id='ab'">

it works like a charm. Please could someone let me know regarding this.

I have three files HTML/XML/XSL

1. html file has the following line

<a href="http://abcd.xml?keyname=abcd" target="_blank">link</a>

2. abcd.xml

<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="abcd.xsl"?>
<Package id="123">
  <base id="ab">
<Package id="456">
  <base id="cd">

3. abcd.xsl

<?xml version='1.0'?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:param name="keyname"/>
<xsl:template match="/">
        <xsl:for-each select="mainpackage/Package">
            <xsl:if test="@id=$keyname">
                <xsl:value-of select="Base/@id"/>
Old March 24th, 2006, 01:24 PM
joefawcett's Avatar
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You cannot do this using a browsers built in ability to transform via a linked stylesheet as parameters in the query string are not passed on to the XSLT as params.
You will have to have a page that reads the query string, parses the parameter value and passes it to the stylesheet before executing the transform.
Alternatively do it server-side, the same sort of process but you won't have to worry about the client's browser type.


Joe (Microsoft MVP - XML)
Old March 24th, 2006, 02:36 PM
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Thanks for your response. Please could you give me an example.

Old March 24th, 2006, 02:46 PM
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Putting a parameter as part of a URL in a hyperlink doesn't have the effect of passing the parameter to the stylesheet. To pass a parameter to a stylesheet when running client-side (which you appear to be doing) you can't invoke the transformation using <?xml-stylesheet?>, you need to invoke it using the Javascript API from your HTML page, passing the parameter explicitly using the addParameter() method.

Michael Kay
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

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