Hi Guys,

I am using following code to convert an XML into XSLT. As one could see I am usinf a template foo recursiveky but I am not able to change value of parameter bid. Could anybody spot the problem?

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html"/>
    <xsl:template name = "foo" match ="/">
        <xsl:param name="bid" select="'0'" />
        <table width = "100%">
            <xsl:for-each select="orgHierarchy/emp">
                <xsl:variable name = "CURRBOSSID"><xsl:value-of select="@bossID"/></xsl:variable>
                    <xsl:if test ="$CURRBOSSID = $bid">
                    <tr>
                        <td><xsl:value-of select = "$bid"/>^^<xsl:value-of select = "@empID"/>^^<xsl:value-of select="@empName" /></td>
                        <td>
                            <xsl:call-template name="foo">
                                    <xsl:with-param name="bid" select = "@empID"/>
                            </xsl:call-template>

                        </td>
                    </tr>
                </xsl:if>
            </xsl:for-each>

        </table>
    </xsl:template>
</xsl:stylesheet>

Regards
Uttam