Hi,

 I am combining multiple XML documents in to one XML documents. The following is my XML file structure.

<component>

<structure>
<section>
<id root="037d359d-d903"/>
<code code="306-1" codeSystem="2.61"/>
</section>
</structure>

<structure>
<section>
<id root="037d359d-d503"/>
<code code="340-1" codeSystem="2.16"/>
</section>
</structure>

</component>

if i run the .xsl the whole <component> to </component> should be copied with XML strucure

my xsl is as follows:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="xml" omit-xml-declaration="no" encoding="UTF-8"/>

<xsl:template match="/">
<xsl:for-each select="index/file">
       <xsl:apply-templates select="document(@filename)/component"/>
     </xsl:for-each>
</xsl:template>

<xsl:template match="component">
<section>
<xsl:apply-templates/>
</section>
</xsl:template>

</xsl:stylesheet>



but if i run the above .xsl, nothing happened. Please help me.

Thanks in advance.
N.Raja

I doubt if you can create a file through the XSL transformation. Yes you can convert one XML in another XML but the converted XML has to be stored by a serverside language. does this gives you an answer?

Rather i am not clear with your question.

---------------------------
Vikrant Korde
3i Infotech, Vashi,
Mumbai, Maharashtra, India.

i got the answer. its working fine now.

the correct .xsl is

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="xml" omit-xml-declaration="no" encoding="UTF-8"/>

<xsl:template match="/">
<xsl:for-each select="index/file">
       <xsl:apply-templates select="document(@filename)/component"/>
     </xsl:for-each>
</xsl:template>


<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>

</xsl:stylesheet>

Thanks.