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Old June 15th, 2006, 08:25 AM
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Default get value, not the path...


New to the world of xslt, and working my way through my first project. 99% there, but I'm having a problem trying to compare two nodes. The $expectedValue variable winds up with the path's location, not with the value of the node at the path's location. How do I accomplish what I'm looking to do?

        <xsl:variable name="myTag" select="name()" />
        <xsl:variable name="uniqueAncestor" select="Step_1_DummyInfo" />
        <xsl:variable name="thisValue" select="." />
        <xsl:variable name="partPath1" select = "concat('../../../../../ExpectedHeader/',$uniqueAncestor)" />
        <xsl:variable name="partPath2" select = "concat($partPath1,'//')" />
        <xsl:variable name="expectedPath" select = "concat($partPath2,$myTag)" />

        <xsl:variable name="expectedValue" select="$expectedPath" />

        <!-- having trouble - the $expectedValue variable contains the STRING, not the Value, how do I get it to pull
             the VALUE so I can test it as follows: -->

               <xsl:when test="$expectedValue = $thisValue">

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Old June 15th, 2006, 08:41 AM
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XSLT doesn't allow an XPath expression to be constructed on-the-fly as a character string, it has to be written literally in the select attribute. Some products (such as Saxon) have an extension function (e.g. saxon:evaluate()) that will allow you to do this.

But I suspect that in your case you can achieve what you want with something like


Michael Kay
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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Old June 15th, 2006, 08:58 AM
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Thanks Michael. That was exactly it, and I spent hours on it before I came here (lesson learned).

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