Hi there,

I have a XSLT that basically replicates the source XML and appends an element at the end of the source XML that contains the time stamp that the source XML was processed by the XSLT.

However, the source XML can be any of any structure, for example, I could have a source XML that contains a structure having details about an inventory of kitchen items and I could have another source XML that have a structure with details of car spare parts.

Each of these different source XML contains a namespace specific to that structure.

I wish to ignore the namespace of the source XML and basically make an exact copy of the source XML and appending the timestamp in an element at the end of the source XML. Is this possible?

Thanks

Yes, you can use the usual design pattern of a modified identity transform:

<xsl:template match="*">
  <xsl:copy>
  <xsl:copy-of select="@*"/>
  <xsl:apply-templates/>
  </xsl:copy>
</xsl:template>

<xsl:template match="/*">
  <xsl:copy-of select="*"/>
  <time><xsl:value-of select="$timestamp"/></time>
</xsl:template>

If you want <time> to be in the same namespace as its parent element, create it using <xsl:element name="time" namespace="{namespace-uri(.)}"/>

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference