node-set function

Bernardo Pacheco · June 19th, 2006, 09:28 AM

Hi,
Is something like this possible?

I have an outside function that returns xml, and I want to store that xml in an xslt variable and further process it. For example:

Code:

<xsl:variable name="getXml">

</xsl:variable>

<xsl:value-of select="exsl:node-set($getXml)/element"/>

Is this possible? If not, what other options do I have? Thanks a lot!

joefawcett · June 19th, 2006, 09:54 AM

That's very possible, most processors have a node-set function. Alternatively the document function will return a document root so you won't need an extension:

Code:

 <xsl:variable name="externalDoc" select="document('http://www.myDomain.com/myXmlSite/myXmlPage.aspx')"/>

In version 2.0 of XSLT you don't need an extension function, even if your variable is like:

Code:

<xsl:variable name="externalDoc"></xsl:variable>

as this is converted automatically to a root node.

--

Joe (Microsoft MVP - XML)

mhkay · June 19th, 2006, 10:45 AM

Many XSLT processors support this kind of functionality, but the details depend on the processor.

If the external function returns a node-set, there will be no need to convert it to a node-set using exsl:node-set.

The more portable approach is to use the document() function (many processors allow you to write a URIResolver or XmlResolver that intercepts the request and returns say a DOM Document node as the result), or to pass the document in as a stylesheet parameter.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference