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Old July 7th, 2006, 10:09 AM
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Default Reading similar elements with different content

Hi all!

i got following problem

I have a xml file as input file and a corresponding xsl file which creats a simple txt file.

First of all the xml:
Code:
<componentlist>

<ccb>
<ip>10.10.21.100</ip>
<ip>10.10.11.200</ip>
</ccb>

<componentlist>

and the xsl:
Code:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text" encoding="ISO-8859-1" indent="no" omit-xml-declaration="yes" />

 <xsl:template match="/">

<xsl:text>
RunAsDaemon: yes
</xsl:text>

<xsl:for-each select="/componentlist/ccb/ip">

<xsl:text>ip = </xsl:text><xsl:value-of select="/componentlist/ccb/ip"/>
<xsl:text>
</xsl:text>
</xsl:for-each>

</xsl:template>

</xsl:stylesheet>
When i create the output file i will always get the same content
like this:
ip = 10.10.21.100
ip = 10.10.21.100

What have i to do to get something like this:
ip = 10.10.21.100
ip = 10.10.11.200

i tried some things like * or // but it wont really works :(

Could you please help me, it should be a trivial problem for you^^

Many thanks
and best regards
Frank

 
Old July 7th, 2006, 01:38 PM
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Default

Change

<xsl:value-of select="/componentlist/ccb/ip"/>

to

<xsl:value-of select="."/>

xsl:for-each iterates over the selected elements by making each one the context node in turn. The way to get the element you are currently processing is ".". If you use a path expression starting with "/", you are selecting from the root of the document, and the result will be unrelated to where you are in the for-each iteration.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference




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