match in a set of nodes

dextermagnific · July 10th, 2006, 07:05 AM

Hi everbody,

i'm trying to match something among a list of items. Typically, i have

Code:

  <xsl:variable name="catch">
    <call>foo1</call>
    <call>printf</call>
  </xsl:variable>

and i want to di something like :

Code:

<xsl:for-each-group select="*" group-ending-with="function_name=$grab/call">

i'd like the '=' to test for each <call> if it matches. Is this can be achieved by some way ?

Thanks

mhkay · July 10th, 2006, 07:45 AM

I don't know what function_name and $grab are, so it's a bit hard to see what you're getting at.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

dextermagnific · July 10th, 2006, 08:05 AM

oh sorry, i changed the names to be more clear.
$grab is $catch
function_name is just a node name
select all node that have the node function_name listed in the $catch variable

mhkay · July 10th, 2006, 08:21 AM

It sounds as if you want

group-ending-with="*[name()=$catch/call]"

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

dextermagnific · July 10th, 2006, 08:28 AM

doesn't seem to work.
i ahe the original xml file :

Code:

  <expr_stmt>
    <expr>
      <call>
        <name>printf</name>
        <argument_list>(
        <argument>
          <expr>"Usage : helloworld &lt;your_name&gt;\n"</expr>
        </argument>)</argument_list>
      </call>
    </expr>;</expr_stmt>

and the transformation :

Code:

<xsl:for-each-group select="*" group-ending-with="if|expr_stmt[child::expr/call[name=$grab/call]]">

doesn't produce the expected result which is : group expressions (expr_stmt) by making the printf function (for example) and the if statements as delimiters

if works if i say [name='printf'] but not [name=$grab/call]. i think it is due to the fact that $grab has many <call> tags.

dextermagnific · July 10th, 2006, 08:33 AM

Oh i tried to print the value of $grab, it displays all the <call> tags, but $grab/call displays nothing.

dextermagnific · July 10th, 2006, 08:38 AM

Ok, i found the trick : group="....[name=$grab/*[name()='call']]"

mhkay · July 10th, 2006, 08:51 AM

Your code looks OK to me. Please post a complete sample source document and stylesheet showing the output you are getting and the output you expect.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

dextermagnific · July 10th, 2006, 08:58 AM

the code is a litte long. but to demonstrate that the previous code doesn't work, take this :

Code:

 <xsl:variable name="grab">
    <call>foo1</call>
    <call>printf</call>
  </xsl:variable>

and

[code]
<xsl:value-of select="$grab/call>
-> nothing

<xsl:value-of select="$grab/*[name()='call']>
-> foo1 print
[code]

thanks

mhkay · July 10th, 2006, 09:55 AM

That suggests you've probably got namespace problems. I asked for complete code so I could help you, but you're leaving me guessing.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference