XSLT Decleration Error.

lafilip · July 20th, 2006, 10:35 AM

Hello all,

I am trying to have a .xsl stylesheet read and parse an XHTML file and output a XHTML file. I keep getting a decleration error. Below is the error and my code. Any help would be greatly appreciated.

Error:

XSLT Error (javax.xml.transform.TransformerConfigurationExcep ti
on): javax.xml.transform.TransformerException:
javax.xml.transform.TransformerEx
ception: stylesheet requires attribute: version

Code:

<xsl:stylesheet xmlns:xsl='http://www.w3.org/1999/xhtml' version='1.0'>
<xsl:output method='xhtml' indent='no' include-content-type='no'
doctype-public="-//W3C//DTD XHTML 1.1//EN"
doctype-system="DTD/xhtml11.dtd" />

Thanks again.

mhkay · July 20th, 2006, 11:24 AM

It's a lousy error message, but your mistake is that you've bound the "xsl" prefix to the XHTML namespace instead of the XSLT namespace.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

lafilip · July 20th, 2006, 11:35 AM

Thank you for the quick response.

Forgive me for my ignorance for I am not that good with namespaces. If I change my code from:

<xsl:stylesheet xmlns:xsl='http://www.w3.org/1999/xhtml' version='1.0'>

to

<xsl:stylesheet xmlns:xsl='http://www.w3.org/1999/XSL/Transform' version='1.0'>

Is this what you were refering to?

mhkay · July 20th, 2006, 11:51 AM

Yes.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

lafilip · July 20th, 2006, 01:53 PM

Thanks again! I got it working now I have one other problem but I will post here to see if anyone else has a solution.

I am trying to change an XHTML font tag to a span tag.

Below is my code:

<xsl:template match="font">
<xsl:element name="span">
 <xsl:attribute name="class">small</xsl:attribute>
 <xsl:copy-of select="local-name() != 'font'" />
 </xsl:element>
</xsl:template>

What is happening is I am replacing the tags fine but I am not getting the text between my original tags I am replacing.

For example the HTML code below
<html>
<head></head>
<body>
test
</body>

</html>

has this output

<html>
<head></head>
<body>
false
</body>

</html>

So I am loosing the content between the tags.

Thanks in advance everyone!!:)

mhkay · July 20th, 2006, 02:33 PM

The value of

local-name() != 'font'

is a boolean which you are copying to your output.

I imagine you want *[local-name() != 'font'] or something similar.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

lafilip · July 20th, 2006, 03:16 PM

I will just want to post one more time I don't want to take all of your time from others.

Here is the portion of code I am having trouble on

<xsl:template match="font">
 <xsl:element name="span">
 <xsl:attribute name="class">small</xsl:attribute>
 <xsl:copy-of select="." />
 </xsl:element>
</xsl:template>

This renders output of the following

<html>
<head />
<body>
test
</body>
</html>

I am trying to keep all of this but the open and close font face tags. I do want the data (in this case 'test') to appear. Below is my desired output.

<html>
<head />
<body>
test
</body>
</html>

mhkay · July 20th, 2006, 04:10 PM

To copy the children of the context node but not the context node itself, use <xsl:copy-of select="child::node()"/>

P.S: I'd recommend my book...

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

lafilip · July 20th, 2006, 04:33 PM

I will def. give it a shot after all the help you provided me with! Thanks again. I will be ordering one soon.