XSLT Row replication in Tables

jsuen · August 6th, 2006, 11:57 PM

Hi,

I wanted to generate a table with a new row (tr) replicated every 4 or so elements (td's). I have found a good example using a calendar month as a data source, and would like the same design principle in my XSLT.

i.e. for:

Code:

<Month>
<day date="1"/>
<day date="2"/>
<day date="3"/>
<day date="4"/>
<day date="5"/>
<day date="6"/>
<day date="7"/>
<day date="8"/>
<day date="9"/>
</Month>

The template applied is:

Code:

    <xsl:template match="day[position() mod 4 = 1]">
    <tr>
        <xsl:for-each select=". | following-sibling::day[position() &lt; 4]">
            <td><xsl:value-of select="@date"/></td>
        </xsl:for-each>
    </tr>
    </xsl:template>

    <xsl:template match="day"/>

The only problem in my application is that I want to fetch the datasource from a http: XML document (i.e. via localhost). Is it possible to do this in the code example above?

I cannot reference the $variable in the <xsl:template match=""> tag, but normally use a variable to assign the external XML datasource to be used.

Any help would be greatly appreciated, thanks

Jon

mhkay · August 7th, 2006, 11:07 AM

Your template rules look fine, you just need to apply them at some point in your code using an instruction such as

<xsl:apply-templates select="document('lookup.xml')/dates/date"/>

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference