how to control optional elements and attributes

NEO1976 · September 1st, 2006, 09:17 AM

Dear all,

Sorry that I am asking many questions today but unfortunately I have another problem.

I am having two optional attributes and they are giving me source and image link of the external icons. I am gonna write down the XSL again but if you want to see the XML file it is the same XML at the loop in XSL topic

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="2.0" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fcs="urn:factiva:developer:v3_0:parsers" xmlns:msxsl="urn:schemas-microsoft-com:xslt" >
<xsl:output method="html" version="4.0" />
<xsl:template match ="/">
<xsl:apply-templates select="SOAP-ENV:Envelope/SOAP-ENV:Body/fcs:GetArticleResponse/fcs:articleResponse/fcs:articleResultSet/fcs:article"></xsl:apply-templates>
</xsl:template>
<xsl:template match="SOAP-ENV:Envelope/SOAP-ENV:Body/fcs:GetArticleResponse/fcs:articleResponse/fcs:articleResultSet/fcs:article">
    <head>
            <title>Factiva Test</title>
            <link href='http://intranet1-t.internal.epo.org/portal/themes/html/epoIntranetCD/cssTheme.css' rel="stylesheet" type="text/css" />
            <link href='http://intranet1-t.internal.epo.org/portal/themes/html/epoIntranetCD/cssPageBody.css' rel="stylesheet" type="text/css" />
    </head>
    <body>
        <div id="epoContentStandard">
        <img src="http://dg1-2.internal.epo.org/_test/Huerol/Factiva/flogostyle1.gif" align="right" />
        <br clear="all"/>
     <xsl:if test="fcs:logo/@source != ''">
        <xsl:variable name="logosource" select="fcs:logo/@source"/>
        <xsl:variable name="logoimage" select="fcs:logo/@image"/>
        <xsl:variable name="logo" select="'fcs:logo/@source'+'/'+'$logoimage'"/>
        <img src= "$logo"/>
        </xsl:if>         <h1 style="margin-bottom:0.3ex;"><xsl:value-of select="fcs:headline/fcs:paragraph"/></h1>
        <p style="margin-bottom:3.5ex;font-size:80%;color:#888888;"><xsl:value-of select="fcs:copyright"/></p>
    <xsl:apply-templates select="//fcs:leadParagraph"/>
    <xsl:apply-templates select="//fcs:tailParagraphs"/>
    <div id="epoFooter">
    <a href='http://www.factiva.com/termsofuse'>Terms of use</a>  ©200X Dow Jones Reuters Business Interactive LLC (trading as Factiva). All rights reserved.
    </div>
        </div>
    </body>
</xsl:template>
<xsl:template match="fcs:leadParagraph">
    <p><strong>
     <xsl:apply-templates select="fcs:paragraph"/>
     </strong>
    </p>
</xsl:template>
<xsl:template match="fcs:tailParagraphs">
    <p>
     <xsl:apply-templates select="fcs:paragraph"/>
    </p>
</xsl:template>

<xsl:template match="fcs:paragraph">
     <p>
        <xsl:value-of select="."/>
     </p>
</xsl:template>

</xsl:stylesheet>

1) What should I write in xsl:if statement
2) How can I add 2 variable with "/" to get a logo variable for img src?

Your attitude determines your altitude

mhkay · September 2nd, 2006, 12:08 PM

I haven't tried to follow the logic in detail. But there's some obvious nonsense here:

<xsl:variable name="logo" select="'fcs:logo/@source'+'/'+'$logoimage'"/>

Firstly, "+" does not do string concatenation in XPath. You want the concat() function. Secondly, there doesn't seem to be any reason to put the first expression in quotes.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

mhkay · September 2nd, 2006, 12:09 PM

This line is wrong too:

<img src= "$logo"/>

It should be

<img src= "{$logo}"/>

I hope you understand why - if not, please ask.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

NEO1976 · September 4th, 2006, 02:27 AM

Thanks Michael so how can I also control these optional elements? ($logosource and $logoimage are optional)What should I write to the if statement?

Secondly is it gonna be

<xsl:variable name="logo" select="concat($logosource, '/',$logoimage)"/>

And sorry for the silly question why should I use {} for <img src= "{$logo}"/>?

Your attitude determines your altitude

mhkay · September 4th, 2006, 02:47 AM

Don't put the variable reference in quotes, otherwise the string "$logosource" will be written to the output.

If $logosource holds an empty sequence then concat() ignores it (treats it as a zero-length string), so you shouldn't need to do anything special for this case - unless of course you want to do something different in this case.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

NEO1976 · September 4th, 2006, 02:58 AM

Ok thanks very much for your help. Actually with your an the others' help I am becoming a good XSL programmer (it takes a while but I find this forum great)

Your attitude determines your altitude