Hello all,
         I'm working in a xslt file that has to filter some of information included in an xml file.This means that information between some kind of tags and this tags themselves don't have to appear in the output xml.The rest of the information must remain unmodified.

I started using <xsl:value of> for writing the information tha must not be filtered in the output xml file.
I'm sure there is an easier and better way than this approach.

I'm looking for advice on which is the best way to tackle this problem using xslt.

Thanks a lot for the help.

Tomi.

The best way of tackling this kind of problem is to write a template rule that copies every element:

<xsl:template match="*">
 <xsl:copy>
  <xsl:copy-of select="@*"/>
  <xsl:apply-templates/>
 </xsl:copy>
</xsl:template>

and then write further template rules for elements you want to treat differently, for example

<xsl:template match="x"/>

deletes any subtree rooted at an x element, while

<xsl:template match="y">
  <xsl:apply-templates/>
</xsl:template>

processes the children of the y element but drops the y element itself.

If that doesn't help, you'll have to explain your problem more specifically.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

I have a problem with <xsl:copy , when I try to copy a node with attributes it only copies the first attribute in the output xml.

i.e

XML INPUT
----------
<?xml version="1.0" encoding="ISO-8859-1"?>
<NodeToCopy a=1.0 b=2.0>
</NodeToCopy>

XML OUTPUT
----------
<?xml version="1.0" encoding="ISO-8859-1"?>
<NodeToCopy a=1.0>
</NodeToCopy>

My code is as follows:

<xsl:template match="NodeToCopy">

<xsl:copy>
    <xsl:copy-of select="@NodeToCopy"/>
</xsl:copy>

</xsl:template>

Ive solved the problem.

Tomi.