Below is my XSLT and my input is a plain text file with a couple of H and Ls'.

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text"/>

<xsl:template match="text()">
  <xsl:call-template name="_replace_string">
    <xsl:with-param name="string" select="." />
    <xsl:with-param name="find" select="'H'" />
    <xsl:with-param name="replace" select="'-H-'" />
    <xsl:with-param name="find2" select="'L'" />
    <xsl:with-param name="replace2" select="'-L-'" />
  </xsl:call-template>
</xsl:template>


<xsl:template name="_replace_string">
<xsl:param name="string" select="''"/>
<xsl:param name="find" select="'find'"/>
<xsl:param name="replace" select="'replace'"/>
<xsl:param name="find2" select="'find2'"/>
<xsl:param name="replace2" select="'replace2'"/>
<xsl:choose>
<xsl:when test="contains($string,$find)">
<xsl:value-of select="concat(substring-before($string,$find),$replace)"/>
<xsl:call-template name="_replace_string">
<xsl:with-param name="string" select="substring-after($string,$find)"/>
<xsl:with-param name="find" select="$find"/>
<xsl:with-param name="replace" select="$replace"/>
</xsl:call-template>
</xsl:when>
<xsl:when test="contains($string,$find2)">
<xsl:value-of select="concat(substring-before($string,$find2),$replace2)"/>
<xsl:call-template name="_replace_string">
<xsl:with-param name="string" select="substring-after($string,$find2)"/>
<xsl:with-param name="find2" select="$find2"/>
<xsl:with-param name="replace2" select="$replace2"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>

</xsl:stylesheet>



I get an error "javax.xml.transform.TransformerException: com.sun.org.apache.xml.internal.utils.WrappedRunti meException: Content is not allowed in prolog." when trying to do a simple string replacement in a text file. Output is a text file too..

Your help is much appreciated..

Thanks

XSLT 1.0 will only accept XML input files. XSLT 2.0 enables other formats to be used but not as the main input, only via functions such as unparsed-text().

--

Joe (Microsoft MVP - XML)

Hi Joe,

thanks for your reply. As per your advise, I have changed the version tag of <xsl:stylesheet> to "2.0" and changed the main input to <xsl:template match="unparsed-text()". So new XSLT is as follows.. with the mentioned changes, i now get a compilation error

ERROR: 'Syntax error in 'unparsed-text()'.'
FATAL ERROR: 'Could not compile stylesheet'

Could you plz help ?

Thanks



<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="text"/>



<xsl:template name="_replace_string">
<xsl:param name="string" select="''"/>
<xsl:param name="find" select="'find'"/>
<xsl:param name="replace" select="'replace'"/>
<xsl:param name="find2" select="'find2'"/>
<xsl:param name="replace2" select="'replace2'"/>
<xsl:choose>
<xsl:when test="contains($string,$find)">
<xsl:value-of select="concat(substring-before($string,$find),$replace)"/>
<xsl:call-template name="_replace_string">
<xsl:with-param name="string" select="substring-after($string,$find)"/>
<xsl:with-param name="find" select="$find"/>
<xsl:with-param name="replace" select="$replace"/>
</xsl:call-template>
</xsl:when>
<xsl:when test="contains($string,$find2)">
<xsl:value-of select="concat(substring-before($string,$find2),$replace2)"/>
<xsl:call-template name="_replace_string">
<xsl:with-param name="string" select="substring-after($string,$find2)"/>
<xsl:with-param name="find2" select="$find2"/>
<xsl:with-param name="replace2" select="$replace2"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>

<xsl:template match="text()">
  <xsl:call-template name="_replace_string">
    <xsl:with-param name="string" select="."/>
    <xsl:with-param name="find" select="'H'"/>
    <xsl:with-param name="replace" select="'-H-'"/>
    <xsl:with-param name="find2" select="'L'"/>
    <xsl:with-param name="replace2" select="'-L-'"/>
  </xsl:call-template>
</xsl:template>


</xsl:stylesheet>

You need to read up on using XSLT, especially version 2.0. Firstly you need to use a version 2.0 processor, the only real option, in my opinion is Saxon, which you read about at www.saxonica.com. Secondly, as I said, you cannot use non XML as your document's primary source you need to bring the content in in a similar way to using the doucument function in version 1.0. The alternative is to pre-process the text beforehand to a simple XML structure before passing it to the transform.

--

Joe (Microsoft MVP - XML)

Attached it the correction i tried, but get an error saying

ERROR: 'Error checking type of the expression 'funcall(unparsed-text, [literal-expr(abc.txt), literal-expr(UTF-8)])'.'
FATAL ERROR: 'Could not compile stylesheet'


thanks for your help




<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="text"/>



<xsl:template name="_replace_string">
<xsl:param name="string" select="''"/>
<xsl:param name="find" select="'find'"/>
<xsl:param name="replace" select="'replace'"/>
<xsl:param name="find2" select="'find2'"/>
<xsl:param name="replace2" select="'replace2'"/>
<xsl:choose>
<xsl:when test="contains($string,$find)">
<xsl:value-of select="concat(substring-before($string,$find),$replace)"/>
<xsl:call-template name="_replace_string">
<xsl:with-param name="string" select="substring-after($string,$find)"/>
<xsl:with-param name="find" select="$find"/>
<xsl:with-param name="replace" select="$replace"/>
</xsl:call-template>
</xsl:when>
<xsl:when test="contains($string,$find2)">
<xsl:value-of select="concat(substring-before($string,$find2),$replace2)"/>
<xsl:call-template name="_replace_string">
<xsl:with-param name="string" select="substring-after($string,$find2)"/>
<xsl:with-param name="find2" select="$find2"/>
<xsl:with-param name="replace2" select="$replace2"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>

<xsl:template match="text()">
  <xsl:call-template name="_replace_string">
    <xsl:with-param name="string" select="unparsed-text('abc.txt','UTF-8')"/>
    <xsl:with-param name="find" select="'H'"/>
    <xsl:with-param name="replace" select="'-H-'"/>
    <xsl:with-param name="find2" select="'L'"/>
    <xsl:with-param name="replace2" select="'-L-'"/>
  </xsl:call-template>
</xsl:template>


</xsl:stylesheet>

You've jumped into the driving seat of a 40-ton truck and you're asking passers-by how to start the engine. The only sane advice is to tell you not to: you need to visit a driving school first. Or in this case, since we're on a Wrox site, find a good book and spend a day reading it.

unparsed-text() can be used in an XPath expression to read a text file, it can't be used in match pattern. Use a named template as the entry point to your transformation, then call unparsed-text() to read the external file into a string.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Hi Mike,

Is this what you meant?

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="text"/>



<xsl:template name="_replace_string">
<xsl:param name="string" select="unparsed-text(document-uri(.))"/>
<xsl:param name="find" select="'find'"/>
<xsl:param name="replace" select="'replace'"/>
<xsl:param name="find2" select="'find2'"/>
<xsl:param name="replace2" select="'replace2'"/>
<xsl:choose>
<xsl:when test="contains($string,$find)">
<xsl:value-of select="concat(substring-before($string,$find),$replace)"/>
<xsl:call-template name="_replace_string">
<xsl:with-param name="string" select="substring-after($string,$find)"/>
<xsl:with-param name="find" select="$find"/>
<xsl:with-param name="replace" select="$replace"/>
</xsl:call-template>
</xsl:when>
<xsl:when test="contains($string,$find2)">
<xsl:value-of select="concat(substring-before($string,$find2),$replace2)"/>
<xsl:call-template name="_replace_string">
<xsl:with-param name="string" select="substring-after($string,$find2)"/>
<xsl:with-param name="find2" select="$find2"/>
<xsl:with-param name="replace2" select="$replace2"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>

<xsl:template match="text()">
  <xsl:call-template name="_replace_string">
    <xsl:with-param name="string" select="''"/>
    <xsl:with-param name="find" select="'H'"/>
    <xsl:with-param name="replace" select="'-H-'"/>
    <xsl:with-param name="find2" select="'L'"/>
    <xsl:with-param name="replace2" select="'-L-'"/>
  </xsl:call-template>
</xsl:template>


</xsl:stylesheet>

Thanks

Are you sure that you're using an XSLT processor that supports XSLT 2.0? Which processor is it?

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

hi mike,

 I am using Sun's transformer javax.xml.transform.Transformer which is the JAXP transformer. But when I replaced the unparsed-text() with a hardcoded string "HHHLL", I get the error - ERROR: 'Content is not allowed in prolog.'

  Does this mean that my transformer doesn't support XSlt 2.0?

Thanks a lot for your help

Question to self, does anyone actually read the answers I post?


--

Joe (Microsoft MVP - XML)