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| XSLT General questions and answers about XSLT. For issues strictly specific to the book XSLT 1.1 Programmers Reference, please post to that forum instead. |
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November 1st, 2006, 11:37 AM
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Why would this skip record #1?
Code:
<xsl:variable name="thisSet" select="substring(@series, 0, 7)"/>
<xsl:for-each select="following-sibling::*[substring(@series, 0, 7) = $thisSet]">
in this case, thisSet = "Nov 06"
So yes, if there are 5 matching records, it only displays 2-5. How can I tweak this to display all five?
dep
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November 1st, 2006, 12:24 PM
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You seem to have forgotten to include any information about the data you are working on.
Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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November 1st, 2006, 12:30 PM
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November 1st, 2006, 12:33 PM
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Code:
<xsl:for-each select="following-sibling::*[substring(@series, 0, 7) = $thisSet]">
<xsl:choose><xsl:when test="@callBid"><xsl:value-of select="@callBid"/></xsl:when><xsl:otherwise>--</xsl:otherwise></xsl:choose>
</xsl:for-each>
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November 1st, 2006, 01:28 PM
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I really hate XSLT.
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November 1st, 2006, 01:46 PM
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Actually, you give me the impression that you really hate programming. Perhaps you're having an off day, but you certainly don't seem to be taking a systematic approach to analyzing your problem and describing it clearly.
Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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November 1st, 2006, 01:58 PM
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Well, our XSLT expert is on vacation this week. I'm trying to dissect his code and figure it out so I can fix his bug... I'm more the DHTML, Javascript guy...
Do you have any idea what I'm doing wrong? Or what more information I could provide to help?
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November 1st, 2006, 02:37 PM
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From your description, I haven't the faintest idea what's wrong. Your snippets of code are meaningless because there's no information about the input document and no context - XPath expressions are very sensitive to context, and many bugs arise from getting the context wrong.
I don't even know what you mean by "record". There's no such thing in XML.
Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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November 1st, 2006, 02:57 PM
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I'm afraid I just don't know enough about it to form the right question.
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