Hi,

I'm currently writing a template to translate someone's xml. I need a way to have a certain node to be passed through as is without removing elements. For example, I have this xml document:

<root>
   <element1>some text</element1>
   <element2>
      <text type="body">
         <p>Some content #8221;</p>
      </text>
   </element2>
</root>


in my xsl template, I want to have everything under the <text> element pass through as is, i.e. keep the "<p>Some content #8221;</p>" as is after translation. right now, all of the <p>'s are removed and the output escaping has been converted after translation. Thanks in advance.

-los

You can copy the content of the text element using

<xsl:template match="text">
  <xsl:copy-of select="child::node()"/>
</xsl:template>

The copy will be logically the same, but not necessarily lexically the same, for example the decimal numeric character reference might be replaced by a hexadecimal reference, or by the character itself if your output encoding includes that character. The original lexical form isn't known to the XSLT processor.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference