hi,

i am trying to display XML string in a webpage using XSLT. this XSL uses another XML file to display labels on that page. here is the code that calls labels XML file.

<xsl:variable name="culture"><xsl:value-of select="VUFile/Language/Culture"/></xsl:variable>

<xsl:variable name="doc" select="concat('/Project/FileViewerResources.',$culture,'.xml')"/>

when i m running my application from c:\inetpub\wwwroot\Project, its running fine, but when i run the same application from another path, say c:\Code\Project, instead of taking the relative path, its still looking for file "FileViewerResources.en-En.xml" in c:\inetpub\wwwroot\Project which is the localhost path.
If i change the default website path in IIS to c:\Code\Project, it works fine.

XML containing actual data which is to be displayed is generated as a string at runtime, so no XML file is created for that.

How do i resolve this? requirement is that it should pick file from relative path and not from localhost directory.

Please Help!
Thanx

Presumably you are passing $doc to the document() function. When you do this, it is interpreted as a relative URI that is relative to the base URI of the stylesheet. If you want it treated as relative to somewhere else (like your "current working directory") you may be able to achieve this using the second argument to the document() function, but the simplest way is probably to pass in the current working directory as a stylesheet parameter and construct the absolute path "by hand". This is all a lot easier in XSLT 2.0 which gives you more control over URI resolution.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

hi,

i tried using stylesheet parameter to hardcode path but error message is displayed --> "Access is Denied"

here is the code i am using:

<xsl:param name="isolang" select="'en'"/>
<xsl:param name="RelPath" select="'c:\Code\Project'"/>
<xsl:variable name="culture"><xsl:value-of select="VUFile/Language/Culture"/></xsl:variable>
<xsl:variable name="doc" select="concat($RelPath,'/Project/FileViewerResources.',$culture,'.xml')"/>
<xsl:variable name="translation" select="document($doc)/labels[lang($isolang)]"/>

Please correct me if i've done something incorrectly. I am new to XSL and XML and still learning. :)