aaaaa

Try

http://www.dpawson.co.uk/xsl/sect2/N7450.html

especially the first item.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Perhaps I answered the wrong question: displaying five items per row of a table is essentially the same problem as displaying five rows per page, except that you presumably want multiple HTML output files. In XSLT 2.0 you can do that with xsl:result-document. In 1.0 there's no standard equivalent, though some products have proprietary extensions; otherwise you need to run the stylesheet N times, once to produce each output page, supplying a parameter to control which page is generated.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

OK, so you are producing multiple tables within one HTML page, not multiple pages as suggested in your original post. In that case, the problem is exactly the same as outputting multiple items in one row of a table, which is discussed in the FAQ I referred you to. The general solution is along the lines

<xsl:for-each select="object[position() mod $N = 1]">
  <table>
    <xsl:for-each select=". | following-sibling::object[position() &lt;= $N]">
      <tr>
        ....

Or perhaps I've misunderstood the question yet again, and you only want to display the first five items and ignore the rest. In that case the above simplifies to

<table>
  <xsl:for-each select="object[position() &lt;= 5]">
    <tr>
      ....

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference