Select node whose child value matches

Fantmx · February 15th, 2007, 11:47 AM

I am trying to select a parent node, that has a child node id that matches a specific value. How would I go about doing this? Right now style sheet looks like this:

Code:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:template match="/">
      <xsl:for-each select="//node">
         <xsl:if test='string(node/guid)=string(9012)'>
            <xsl:value-of select="."/>
         </xsl:if>
      </xsl:for-each>
   </xsl:template>
</xsl:stylesheet>

The data is as follows:

Code:

<node>
   <display>Some Text</display>
   <guid>1234</guid>
   <node>
      <display>More text</display>
      <guid>5678</guid>
   </node>
   <node>
      <display>Another node</display>
      <guid>9012</guid>
   </node>
</node>

Thank you!

mhkay · February 15th, 2007, 12:21 PM

<xsl:for-each select="//node[guid=9012]">
<xsl:value-of select="."/>
</xsl:for-each>

When the current node is a <node> element, doing node/guid means child::node/child::guid, and your <node> element doesn't have a child called <node>.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

mhkay · February 15th, 2007, 12:23 PM

Sorry, I was too quick. Your node does have a child::node. So your code looks OK, except it can be shortened to

<xsl:for-each select="//node[node/guid=9012]">...

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Fantmx · February 15th, 2007, 01:11 PM

That doesn't seem to work. I am using XTrans to test all of my XSLT, which uses the Microsoft engine, since I will ultimately be using this in C# code. I should have stated that the node with the matching guid may be at any level. Any other suggestions?

mhkay · February 15th, 2007, 01:32 PM

Please supply your complete input, complete code that "isn't working", the output it produces, and the output that you want.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Fantmx · February 16th, 2007, 04:54 PM

I figured it out. I replaced the string(xxx) with single quotes and it works fine now. Thank you.