I have an xml and i transform it with xslt into plain text....

this is a part of xslt:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:str="http://exslt.org/strings">
<xsl:output method="text" encoding="utf-8" media-type="text/plain" />
<xsl:include href="str.align.template.xsl"/>
<xsl:preserve-space elements="*" />
<xsl:template match="row">
<xsl:variable name="c0_pad"><xsl:text>#x20;#x20;#x20;#x20;#x20;# x20;#x20;#x20;#x20;</xsl:text></xsl:variable>
<xsl:variable name="c0_string"><xsl:value-of select="@Symbol"/></xsl:variable>
<xsl:variable name="c0_align">left</xsl:variable>
<xsl:call-template name="str:align">
<xsl:with-param name="string" select="$c0_string"/>
<xsl:with-param name="padding" select="$c0_pad"/>
<xsl:with-param name="alignment" select="$c0_align"/>
</xsl:call-template>
<xsl:text>#x0d;</xsl:text>
<xsl:text>#x0a;</xsl:text>
</xsl:template>
</xsl:stylesheet>

but open it in notepad i cannot see newlines, why...
i need a crlf, how can i take it?
i have tried many things but no luck.....

Can you help me???

I see line-break with the following code in Notepad:
Regards,
Armen

Thanks.....

but it was the first syntax i tried and i was not lucky.
After this i tried to brake it in two lines:
    <xsl:text>#x0d;</xsl:text>
    <xsl:text>#x0a;</xsl:text>
but also nothing...

Do you know nothing else...????????

But it's ok when I'm testing the code I posted... What XSLT processor you are using?