Hi,

Is it possible to expand default values in XSLT? I have the following XML Schema:

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified">
<xs:element name="Config">
  <xs:complexType>
    <xs:sequence>
        <xs:element name="Element1" type="xs:boolean" default="true"/>
        <xs:element name="Element2" type="xs:int"/>
        <xs:element name="Element3" default="YES">
            <xs:simpleType>
                <xs:restriction base="xs:string">
                    <xs:enumeration value="YES"/>
                    <xs:enumeration value="NO"/>
                </xs:restriction>
            </xs:simpleType>
        </xs:element>
        </xs:sequence>
    </xs:complexType>
</xs:element>
</xs:schema>

And I have the following XML:
<?xml version="1.0" encoding="UTF-8"?>
<Config xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="Config.xsd">
        <Element1>true</Element1>
        <Element2>123</Element2>
        <Element3/>
</Config>

Which when I put through the following stylesheet:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="text" encoding="UTF-8" indent="no"/>
<xsl:strip-space elements="Config"/>

<xsl:template match="/Config/*">
  <xsl:value-of select="name()"/>
  <xsl:text>=</xsl:text>
  <xsl:value-of select="."/>
  <xsl:text>#xa;</xsl:text>
</xsl:template>

</xsl:stylesheet>

I get the following output:
Element1=true
Element2=123
Element3=

Is there anyway I can get XSLT to output the default value of YES for Element3 as defined in the schema? I am using C++ Xalan 1.10.

thanks
  Alex

The obvious way to do this is to use a schema-aware XSLT 2.0 processor such as Saxon-SA. This will do a lot more than expanding default attributes, it will also enable you detect errors in your stylesheet code more quickly: an XSLT processor can also use type information for optimizing your code.

If all you want from your schema, however, is expansion of defaults then you may be able to arrange for the output of your schema processor to be piped into your XSLT 1.0 processor. For example I think this will happen if you implement the validation as a JAXP ValidatorHandler (but you're using C++, I don't know about that).

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference