how to do it in xslt?

newtoxml · October 31st, 2003, 08:07 PM

I have a xml file looks like this:

<root>
     <L1>a</L1>
     <L2>b
         <L3>c</L3>
     </L2>
</root>

In my xslt file, I do a template match to get to <L3>

<xsl:template match="L2/L3">
need to use the value of L1.
</xsl:template>

Assuming that I get to the node of L3. Now, my question is, how do I get the value of L1 inside of the that match template? Is there a global variable or something in xslt so I can store the L1's value in that global variable and use it in the match template?

Can anyone tell me how I can do this in xslt? Please give me some details because I am still learning this stuff :-)

Thanks in advance.

joefawcett · November 1st, 2003, 04:53 AM

Well it's not clear how you wish to access it, there are a number of possibilities, these are shown together with the xpath which would retrieve it from within the template matching L2/L3:

1) As the first child of the document element:
  (/*/*)[1]
2) As the first preceding sibling of the parent:
  ../preceding-sibling::*[1]
3) As the preceding element:
  (preceding::*)[1]

Here's a stylesheet to see:

Code:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" method="xml" version="1.0" encoding="UTF-8" />
  <xsl:template match="/">
    <xsl:apply-templates select="root/L2/L3"/>
  </xsl:template>
  <xsl:template match="L2/L3">
    (/*/*)[1] gives<xsl:text>#x0a;</xsl:text>
    <xsl:value-of select="(/*/*)[1]"/><xsl:text>#x0a;</xsl:text><xsl:text>#x0a;</xsl:text>
      ../preceding-sibling::*[1] gives<xsl:text>#x0a;</xsl:text>
    <xsl:value-of select="../preceding-sibling::*[1]"/><xsl:text>#x0a;</xsl:text><xsl:text>#x0a;</xsl:text>
    (preceding::*)[1] gives<xsl:text>#x0a;</xsl:text>
    <xsl:value-of select="(preceding::*)[1]"/><xsl:text>#x0a;</xsl:text><xsl:text>#x0a;</xsl:text>    
</xsl:template>
</xsl:stylesheet>

Joe (MVP - xml)

armmarti · November 1st, 2003, 05:05 AM

In any case you must use an XPath expression to get the node you want:

a) using a variable:
declare this variable before all templates

Code:

  <xsl:variable name="l1" select="/root/L1"/>

then use the variable in the template body:

Code:

  <xsl:value-of select="$l1"/>

b) or simply inside the template body write:

Code:

  <xsl:value-of select="/root/L1"/>

c) or you can get the node "L1" from the current node(L2/L3) in the template body:

Code:

  <xsl:value-of select="../preceding-sibling::L1"/>

Regards,
Armen

pulavarthi · November 1st, 2003, 06:30 AM

Hi

There u can use <xsl:value-of select"."/> tag this will print the text between the L3 Tag.

bye
Pulavarthi

Quote:

quote:Originally posted by newtoxml

I have a xml file looks like this:

<root>
     <L1>a</L1>
     <L2>b
         <L3>c</L3>
     </L2>
</root>

In my xslt file, I do a template match to get to <L3>

<xsl:template match="L2/L3">
need to use the value of L1.
</xsl:template>

Assuming that I get to the node of L3. Now, my question is, how do I get the value of L1 inside of the that match template? Is there a global variable or something in xslt so I can store the L1's value in that global variable and use it in the match template?

Can anyone tell me how I can do this in xslt? Please give me some details because I am still learning this stuff :-)

Thanks in advance.