Please help me out with XML-HTML tranformation

tutukun · May 13th, 2007, 01:52 AM

Hi,
I'm trying some xml to html examples, and I'm kinda stuck. For example i have the following xml

Code:

 <para>
        Hi pls visit my website at <url>http://www.abc.com</url>.
 </para>

Could anyone help me form it into something that look like:

Quote:

quote:Hi pls visit my website at http://www.abc.com

using XSLT?

Sorry for my bad english.

Thank you Smile

joefawcett · May 13th, 2007, 02:40 AM

You say you're stuck but you don't say where. What XSLT do you have at the moment?

--

Joe (Microsoft MVP - XML)

tutukun · May 13th, 2007, 03:19 AM

hi, sorry here is what I have

<xsl:template match="para">
        <xsl:value-of select="."/>
        <p>
            <xsl:apply-templates select="url"/>
        </p>
</xsl:template>

<xsl:template match="url">
      <a>
        <xsl:attribute name="href">
            <xsl:value-of select="//url">
        </xsl:attribute>
      </a>
</xsl:template>

But I keep getting output similiar to this:

Hi pls visit my website at http://www.abc.com http://www.abc.com

joefawcett · May 13th, 2007, 04:35 AM

Your main error is not employing the context correctly. For example when you are inside the url template the context node is url so you can access it via '.', you don't need to query the whole document using //url.

Code:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:template match="/">
    <html>
      <body>
       <xsl:apply-templates select="para"/>
      </body>
    </html>
  </xsl:template>

  <xsl:template match="para">
    <xsl:value-of select="text()[1]"/>
    <xsl:apply-templates select="url"/>
  </xsl:template>

  <xsl:template match="url">
    <a href="{.}"><xsl:value-of select="."/></a>
  </xsl:template>

</xsl:stylesheet>

--

Joe (Microsoft MVP - XML)

mhkay · May 13th, 2007, 04:41 PM

<xsl:template match="url">
      <a>
        <xsl:attribute name="href">
            <xsl:value-of select="//url">

"//url" means "All the url elements in the document". So every time you match a URL, you output the values of all the URLs in the document. At least, that's what XSLT 2.0 does. In XSLT 1.0, when xsl:value-of is given a node-set then it outputs the value of the first node in the set.

You want "." here, to mean "the current url element".

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference