xpath query

blitzer · May 18th, 2007, 07:46 PM

I got a xml code:
<list>
    <student>
        <name>dave</name>
        <adres>old trafford</adres>
        <adres>manchester,england</adres>
    </student>
    <student>
        <name>paul</name>
        <adres>old trafford</adres>
        <adres>manchester,england</adres>
    </student>
</list>

how do i output name+ the 2 adress lines.

I tried:
<xsl:template match="/">
    <xsl:for-each select="list/student">
        <xsl:value-of select="name"/>
        <xsl:value-of select="adres"/>
    </xsl:for-each>
</xsl:template>
But it only outputs 1 line of address.How do i output both the lines of address ?

joefawcett · May 19th, 2007, 02:44 AM

Instead of:

Code:

<xsl:value-of select="adres"/>

try

Code:

<xsl:apply-templates select="adres"/>

and add a template:

Code:

<xsl:template match="adres">
  <xsl:value-of select="."/>

  <xsl:if test="position() != last()">, </xs:if>  
</xsl:template>

Your code would work in version 2.0 where value-of returns a space separated list rather than just the first matching node.

--

Joe (Microsoft MVP - XML)

mhkay · May 19th, 2007, 03:54 AM

You iterate over the adres elements exactly the same way as you iterate over the student elements, with an xsl:for-each.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference